If you run the contour walker for N=2, you will get a lot of hits for a sum of 2, for instance:
10,841,593,393 was the largest value found when I stopped the search.
Inspection reveals that these are all of the form:
(6n^3+1)^3-(6n^3-1)^3-(6n^2)^3 = 2
The above list starts with n = 2. if we replace the ±1 in the above expression with ±a^3 we can get the more general:
(6n^3+a^3)^3-(6n^3-a^3)^3-(6n^2a)^3=2a^3.
We can also multiply all the terms by b, and thus generate an infinite number of sums that add up to any constant of the form 2*a^9*b^3.
(c) John Whitehouse 2021 - 2023